1. The problem statement, all variables and given/known data A gas expands in volume from 26.7mL to 89.3mL at constant temperature. Calculate the work done (in joule) if the gas expands: i) against a vacuum ii) against constant pressure of 1.5atm iii) against a constant pressure of 2.8 2. Relevant equations w= -PdV gas expands at constant temperature= isothemic expansion 3. The attempt at a solution i) I'm not sure about this part ii) 1atm= 1.013x10^5 Pa P= 1.5x 1.013x10^5 = 151950 Pa I converted ml to m^3 (am i supposed to do this?) 26.7/ 1x10^6 = 2.67x10^-5 m^3 8.93/ 1x10^6 = 8.93x10^-5 m^3 w= -PdV w= - (151950)x (8.93x10^-5 -2.67x10^-5) w= -9.512 J iii) I did the same working for this part as above P= 2.8 x 1.013x10^5 P= 283640 Pa w= - (283640) x (8.93x10^-5 -2.67x10^-5) w= -17.756 J am I doing this correct? or do I use the equation ln V2/V1 P ?