Expectation formula in Dirac notation.

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 7K views
david.makcenz
Messages
1
Reaction score
0
Expectation value of operator A is given by following formula in Dirac notation.

<A> = <x|A|x>

where
A : Operator
<A> : Expectation value of A
|x> : State

Somehow I am unable to convince myself that this formula is true.
Would someone please explain it to me?

Thanks
 
Physics news on Phys.org
[tex]\langle \hat{A} \rangle = \langle x|\hat{A}|x \rangle = \int \psi_{x}^{"*"} \hat{A} \psi_{x} \,d \tau[/tex]

This is the expectation value postulate of quantum mechanics.

If the wavefunction [tex]\psi_{x}[/tex] is not an eigenfunction of the operator [tex]\hat{A}[/tex] then the measured value of the observable [tex]A[/tex] is variable. When [tex]\psi_{x}[/tex] is normalized such that
[tex]\int \psi_{x}^{"*"}\psi_{x} \,d \tau=1[/tex]
the expectation value above yeilds the average measurement of all possible measurements of [tex]A[/tex]. (Note that [tex]d \tau[/tex] indicates an integration over all space.) This works because, since [tex]\hat{A}[/tex] is an Hermitian operator, its eigenvectors form an orthonormal basis. It follows that any function can be written as an infinite linear combination of eigenfunctions of [tex]\hat{A}[/tex].
 
Last edited: