Expectation Value of Position for Even Wavefunction

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The discussion focuses on calculating the expectation values for position and momentum of two wavefunctions, ψ0 and ψ1, where ψ0 is an even function and ψ1 is an odd function derived from ψ0. The expectation value for position, <x>, is determined to be zero for both wavefunctions due to their symmetry properties. For momentum, <p>, the expectation value is also concluded to be zero, as the momentum operator applied to the even wavefunction leads to an odd function, resulting in a zero integral. The importance of symmetry in wavefunctions is emphasized in determining these expectation values. The calculations highlight the relationship between the properties of wavefunctions and their implications in quantum mechanics.
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Homework Statement



Hello, I need to calculate the expectation value for position and momentum for a wavefunction that fulfills the following relation:

ψ0(-x)=ψ0(x)=ψ*0(x)

The wave function is normalised.


Homework Equations



There is also a second wave equation that is orthogonal to the first:

ψ1=Nd0/dx

I also need to calculate <x> and <p> for this wavefunction, also normalised.


The Attempt at a Solution



I am tempted to go ahead and say that the expectation value for position for both wavefunctions is 0, as they are both even. As for momentum I am not certain as to how i should proceed, inserting the relevant operator just seems to indicate to me momentum will be zero.
 
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Correction:

ψ1=Ndψ0/dx
 
I should point out that ψ1 is actually an odd function, being the derivative of an even function, it is not even as i stated earlier.
 
Just write down the expectation values of position and momentum in terms of the wave function (the position representation of the quantum state). Then discuss the mathematics given the symmetry properties, i.e., either even or odd, of the wave functions.
 

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