Expectation Value of Q in orthonormal basis set Psi

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SUMMARY

The expectation value of the operator Q in an orthonormal basis set { |ψ1>, |ψ2>,...,|ψn>} is calculated using the formula = ∑j=1n qj |<Φ| ψj>|^2. Each basis vector |ψj> is an eigenvector of Q, satisfying the equation Q|ψj> = qj|ψj>. The particle state |Φ> can be expressed as a linear combination of the basis vectors, leading to the conclusion that the expectation value is derived from the inner products of |Φ> with the basis states.

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Decadohedron
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Homework Statement



Suppose that { |ψ1>, |ψ2>,...,|ψn>} is an orthonormal basis set and all of the basis vectors are eigenvectors of the operator Q with Q|ψj> = qjj> for all j = 1...n.

A particle is in the state |Φ>.

Show that for this particle the expectation value of <Q> is

j=1nqj |<Φ| ψj> |^2

Homework Equations

The Attempt at a Solution



1. |Φ> = ∑an| ψn> with an = <Ψn|Φ>

2. Q|ψj> = qjΣbnn>, with b_n = <Ψn| Ψj>

After introducing the delta
a_m = QΣb_nΨ_n

Then, I should have

<Q> = Σ | Q |^2

= Σ | Q|Ψ> | ^2
= Σ q_j |Σ b_n | Ψ_n|^2
= Σ q_j |a_m|^2
= Σ q_j | <Ψ_m|Φ> |^2

Then by taking the inner product

= Σ q_j | < Φ|Ψ> | ^2

That's about as close as I could get but I have this general feeling of being very wrong. Not sure how else to approach this.
 
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Nowhere in your attempt at a solution is there the starting point for the expectation value of the operator, namely ##<\Phi|Q|\Phi>.## Start from that and then use what you already know, namely ##|\Phi>=\sum <\psi_n|\Phi>|\psi_n>## and ##Q|\psi_n> = q_n|\psi_n>.## Note that both the bra ##<\Phi|## and the ket ##|\Phi>## in the expectation value bra-ket are summations.
 
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