- #1

- 13

- 0

i dont really understand what does the "if 1 tail occurs , no one wins. how do you set up that?

i only set up up to ( $26*3/8) + ($13* 2/8) -(26* 4/8) how do i set up the if 1 tail occurs?

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- Thread starter mtingt
- Start date

- #1

- 13

- 0

i dont really understand what does the "if 1 tail occurs , no one wins. how do you set up that?

i only set up up to ( $26*3/8) + ($13* 2/8) -(26* 4/8) how do i set up the if 1 tail occurs?

- #2

Stephen Tashi

Science Advisor

- 7,633

- 1,492

i dont really understand what does the "if 1 tail occurs , no one wins. how do you set up that?

Use $0 for the winnings.

i only set up up to ( $26*3/8) + ($13* 2/8) -(26* 4/8) how do i set up the if 1 tail occurs?[/

Your probabilities add up to more than 1, so they are wrong.

- #3

- 13

- 0

($26*3/8) + ($13* 2/8) -(26* 4/8) + 0 (1/8)

isnt that still the same?

so what is wrong with my equation?

- #4

Stephen Tashi

Science Advisor

- 7,633

- 1,492

Yes. The zero just shows a grader than you know what you are doing.if i use 0 for the winnings that 1 tail occurs that just means i add 0 to the end of my equation?

($26*3/8) + ($13* 2/8) -(26* 4/8) + 0 (1/8)

isnt that still the same?

so what is wrong with my equation?

You have computed the probabilities incorrectly. For example, the probability of getting 2 heads in 3 tosses isn't 2/8. Of the 8 possible results of tossing 3 coins, there are 3 possible ways that one can get 2 heads and 1 tail.

- #5

- 13

- 0

You have computed the probabilities incorrectly. For example, the probability of getting 2 heads in 3 tosses isn't 2/8. Of the 8 possible results of tossing 3 coins, there are 3 possible ways that one can get 2 heads and 1 tail.

oh wow, i can't believe i made such a stupid mistake, thank you for helping me out

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