Explain Vceq & Icq in Collector-Base Bias Config.

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SUMMARY

The discussion focuses on the concepts of Vceq and Icq in the context of collector-base bias configuration in transistor circuits. Vceq represents the collector-emitter voltage at the quiescent point (Q point), while Icq denotes the collector current at this same operating point. The base resistance (Rb) is calculated using the formula Rb = (Vcc - Vbe - IcRl) / Ib, although an alternative approximation of Rb = Vceq / Ib is also mentioned. The discussion emphasizes the importance of using upper-case subscripts for DC bias points and applying Kirchhoff's voltage law for accurate circuit analysis.

PREREQUISITES
  • Understanding of transistor biasing techniques
  • Familiarity with Kirchhoff's voltage law (KVL)
  • Knowledge of quiescent point (Q point) in transistor circuits
  • Basic circuit analysis skills involving resistances and voltages
NEXT STEPS
  • Study the derivation of transistor biasing equations in detail
  • Learn about the significance of the quiescent point in amplifier design
  • Explore the impact of neglecting Vbe in biasing calculations
  • Review practical examples of collector-base bias configurations
USEFUL FOR

Electrical engineers, electronics students, and hobbyists interested in transistor circuit design and analysis will benefit from this discussion.

ranju
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the base resistance in collector to base bias configuration is given by
Rb=Vcc-Vbe-IcRl / Ib
now , in a question only the value of Vceq is given & they found Rb as Rb=Vceq/Ib.!
what is Vceq over here..?? and another quantity Icq is used..what are these two quantities..please explain a bit..
 
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ranju said:
the base resistance in collector to base bias configuration is given by
Rb=Vcc-Vbe-IcRl / Ib
Isn't this equation needing a set of paentheses? Here, borrow a spare pair of mine: ( )

now , in a question only the value of Vceq is given & they found Rb as Rb=Vceq/Ib.!
what is Vceq over here..?? and another quantity Icq is used..what are these two quantities..please explain a bit..
Vceq would be the value of Vce at the quiescent point, the "Q point".
Icq is the value of collector current at the Q point

The Q point is the DC operating point that your bias arrangement sets.

BTW, it is not correct to use lower-case subscripts for these DC bias points, you should be using upper-case. There is a strict convention to follow. VCEq is the quiescent C-E voltage.

I hope that answers your questions.
 
that means VCEq = Vcc-Vbe-IcRL...?
 
ranju said:
that means VCEq = Vcc-Vbe-IcRL...?
Sketch your circuit. Mark on it a closed loop. You won't be able to draw any closed loop to confirm your quoted guess. So your guess must be wrong.

Apply Kirchoff's voltage law to any complete loop on the schematic to find that loop's equation.
 
This is the given circuit with which I was referring to ..
Here in the solution , they took RB=VCEQ / IB
and if we apply KVL we ger RB= VCC-VBE-ICRL / IB
we can neglect VBE in comparison to VCC , so is VCEQ=VCC-ICRL...??
 

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ranju said:
This is the given circuit with which I was referring to ..
Here in the solution , they took RB=VCEQ / IB
Approximately.

and if we apply KVL we ger RB= VCC-VBE-ICRL / IB
Approximately. But what happened to those extra parentheses I leant you?

we can neglect VBE in comparison to VCC
There is no good reason for doing so, biasing need not be quite so rough and ready.

so is VCEQ=VCC-ICRL...??
Approximately. So what is being neglected in making this approximation?
 
so is that a generalised formula for CE voltage at quiscient point...this what I was asking...
 

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