Explain why some noble gases such as Xe will form compounds

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SUMMARY

Noble gases such as Xenon (Xe) can form compounds due to their lower ionization energy compared to Neon (Ne), making Xe more reactive. The difference in ionization energy is approximately 1000 kJ/mol, allowing Xe to lose electrons more easily. In contrast, Ne remains stable and does not readily form compounds. Additionally, in ethene (H2C=CH2), the carbon atoms are sp2 hybridized, resulting in a trigonal planar arrangement with a double bond formed by sigma and pi molecular orbitals.

PREREQUISITES
  • Understanding of ionization energy and its impact on reactivity
  • Familiarity with hybridization concepts, specifically sp2 hybridization
  • Knowledge of molecular orbital theory and bonding types
  • Basic grasp of chemical bonding in alkenes, particularly ethene
NEXT STEPS
  • Research the ionization energies of noble gases and their reactivity trends
  • Study sp2 hybridization and its implications for molecular geometry
  • Explore molecular orbital theory in detail, focusing on sigma and pi bonds
  • Investigate the formation of compounds involving other noble gases like Krypton (Kr)
USEFUL FOR

Chemistry students, educators, and researchers interested in the reactivity of noble gases and the principles of chemical bonding in organic compounds.

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sorry but this si really hard for me i don't understand these 2 question.

Explain why some noble gases such as Xe will form compounds and some such as Ne will not?


What kinds of orbital arrangemenets contribute to the bonding in ethene

H2C = CH2

thats a double bond

i tried and i don't understand.
 
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trigonal planar

All atoms will be on a flat plane with the Hydrogens coming off at a 120 angle.

Nautica
 
Xenon has a much lower ionization energy than neon, by a difference of a 1000 or so kJ/mol. In other words it will take less energy to strip an electron off xenon and make it reactive compared to neon. It still takes a lot of energy though.

In ethene, the carbons are sp2 hybridized.
/:up spin
\:down spin

CH2=CH2
2s _/\_
2p _/_ _/_ __

make
sp2 _/\_ _/_ _/_
and the leftover 2p __
with two spots for the two hydrogens and an empty 2p orbital that overlaps with the adjacent carbons empty 2p to make the pi bond. I hope that wasn't too confusing. Do you have a textbook that you use with your class?
 
Last edited:
I'm pretty sure they've formed compounds with neon. In fact I think that was the first noble gas they've got to form compounds.
 
Uh, nope --- Xe first, then Kr. I s'pose radon's the most reactive of the group, but the 4 day half-life takes all the fun out of playing with it.
 
Elements farther down the column have higher quantum numbers and as a result the valence electrons have less effective nuclear charge; thus low ionization energy and most importantly of all they are able to be polarized. An example of this is their ability to more easily form van der wal bonds. Simply said, Xe's electrons are more "available" due to its outer location as well as its polarization characteristics.
Remember though that these compounds are most likely induced-ionic or induced dipole bonds. The stability of nobles gases and thus their instabilty as compounds can be explained through molecular orbital theory.

Hybridized SP2 atomic orbitals form sigma molecular orbitals with SP2 and S orbitals, overlapping Pz orbitals forms the pi shaped molecular orbital.

Hope this helps.
 

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