First note that the wave function gives you (by way of [itex]|\psi|^2[/itex]) the volume probability density: the probability per unit volume of finding the particle at or near a given point.
To simplify the discussion, suppose we have a uniform volume probability density [itex]\rho[/itex].
Now ask the question, what is the probability that the particle is located a distance r from some point (e.g. the center of a sphere)? Loosely speaking, if r is large, there are more points at that distance; and if r is small, there are fewer points at that distance. So the total probability of being at some point at distance r increases as r increases, and decreases as r decreases.
To make this more precise, consider the probability that the particle is located in a thin spherical shell of thickness dr and radius r. For a uniform volume probability density, the probability of being in the shell is approximately (thickness of shell)(area of shell)(probability density) = [itex]4 \pi r^2 dr \rho[/itex]. Factoring out the thickness of the shell we have the radial probability density [itex]4 \pi r^2 \rho[/itex]. Even though the particle has the same chance of being located at or near the center, as at any other point, it has a smaller probability of having a smaller r than a larger r.
The hydrogen 1s wave function and volume probability density are not uniform, but the same idea applies, when we switch from volume probability density to radial probability density.