Explanation about Megaohmeter (Megger)

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The discussion explains that the voltage output from a Megger, typically 500 to 1000V, is not dangerous due to its high internal impedance, which limits the current to safe levels. The original Megger used a hand-cranked alternator with many wire turns to generate voltage while maintaining a high output impedance, making it a non-destructive testing tool. The internal resistance of several tens of MΩ ensures that only a fraction of a milliamp flows, reducing the risk of electric shock. The design features a dual-coil meter movement that accurately measures resistance regardless of the handle's turning speed. The conversation briefly veers into the sealing of electrical cables through submarine hulls, indicating a potential topic for further discussion.
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Can someone explain to me why voltage from Megger(500, 1000V) isn't that dangerous, why current is small?
Thanks.
 
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Large internal impedance
 
The (original?) Megger consisted of a hand cranked alternator with many turns of wire on the coil - to produce the output of 500V, ( up to 5kV, for some models) The output impedance is deliberately made very high (by making th alternator 'not very good') so that it is 'safe' to use and also it is a non-destructive tester. The (series) internal resistance is several tens of MΩ and that limits the current that's available to a safe value. With only a fraction of a mA flowing through you, the output volts would drop to a safe level.
http://www.theautomationstore.com/megger/ The meter movement was cleverly arranged so that there were two coils, unlike the normal microAmmeter, which has one. The current into the test device was fed to one coil and the current through an internal reference resistor was fed to the other. The needle position ended up where the turning effect of the two coils balanced each other out. This 'ratiometer' arrangement gave a good measurement of the resistance under test, irrespective of how fast you turned the handle. (Smart, don't you think - for ancient Engineers with no access to solid state technology!?)
 
And when the megger wasn't enough, there was the HighPot tester in industrial facilities.

Did'ja ever wonder how electrical cables are sealed through submarine hulls?
 
" Did'ja ever wonder how electrical cables are sealed through submarine hulls?"

Yes. Stranded conductors would require a strong water blocker. A bushing with a solid conductor might work better.
 
Doug Huffman said:
Did'ja ever wonder how electrical cables are sealed through submarine hulls?
A truly random (but interesting) change of course for the thread. Perhaps another thread?? I'm sure the mods would prefer it that way. :smile:
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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