Explicit Solutions to this equation

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Homework Help Overview

The discussion revolves around finding an explicit solution to the equation -2x^2y + y^2 = 1 and the differential equation 2xydx + (x^2 - y)dy = 0. Participants are exploring the relationships between these equations and the nature of their solutions.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss deriving the equations to show that one is an implicit solution of the other. There are attempts to isolate y and find an explicit solution, with some expressing confusion about the process. Questions arise regarding the implications of y not being equal to zero and the challenges of isolating y in a quadratic form.

Discussion Status

There is active exploration of the problem, with participants sharing their attempts and insights. Some guidance has been offered regarding treating the equation as a quadratic in y, but no consensus has been reached on the explicit solution.

Contextual Notes

Participants note that y is not isolated in their attempts, and there is an acknowledgment of the quadratic nature of the equation in y, which complicates the process of finding an explicit solution.

vipertongn
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Homework Statement


explicit solution of -2x^2y+y^2=1; 2xydx+(x^2-y)dy=0?


The Attempt at a Solution


I was able to find that dy/dx=-2xy/(x^2-y) which is the implicit solution of the equation. I pretty much derived both of the equations to make sure they are both equal to one another... Not sure if that's how I could prove that the first order DE has them as an implicit solution...I'm just confused entirely... Now I'm trying to get the explicit solution...but that's just very hard considering the variables are stuck to each other.
 
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How about after finding the derivative of both, set them equal and simplify? Notice that y\neq 0.
 
deriving both gives the same answer. Pretty much showing that one of them is an implicit solution. so y'= -2xy/(x^2-y) for both of them. haha in my first post I indicated what you said for me to do there
 
Oh sorry I forgot to mention that you should find an explicit solution of y(x) by realizing that it is a quadratic in terms of y.
 
ya, every time i try to get y by itself it ends up always not working out like y is always not isolated...
 
It is a quadratic equation in y!

y2-(2x2)y-1=0

Pretend that 2x2 is some number b.

ehild
 

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