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Exploding shell at the top of its trajectory

  1. Nov 25, 2012 #1
    "After a shell explodes at the top of its trajectory, the center of gravity of the fragments has an acceleration, in the absence of air resistance, equal to g and downward."

    Why isn't there an x-component?

    I get why there would be a downward component with a = g, but shouldn't there at least be an increase in acceleration in the x dimension? Does it not have an acceleration in the x direction just because it's traveling at a constant velocity in the x direction (i.e., does it assume the explosion doesn't affect velocity in the x direction, albeit momentarily)?
     
  2. jcsd
  3. Nov 25, 2012 #2
    1/ it was fired straight upwards

    2/ shaped charge setup to fire straight downwards

    TBH it sounds like a really stupid question. If it "explodes" some portion of the fragments will expand outwards in all directions ...
     
  4. Nov 25, 2012 #3
    Ah. My bad. I was assuming for some reason that it wasn't fired straight up. And yeah, I just wish it said split or something rather than "explodes". Anyway, I appreciate the help : D
     
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