A 36-kg shell is fired from a gun with a muzzle velocity 185 m/s at 59 degrees above the horizontal. At the top of the trajectory, the shell explodes into two fragments of equal mass. One fragment, whose speed immediately after the explosion is zero, falls vertically. What is the horizontal speed of the other fragment? Hint: Use conservation of linear momentum at the point of explosion. My gut approach to this problem was that I could use the angle to find the vertical and horizontal components of velocity. If we assume no friction, the horizontal component of acceleration should remain constant. It is apparently the wrong answer. I don't really understand how to use conservation of linear momentum here? Any help is much appreciated! Thanks!