- #1
Jacob Gawel
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Assuming the resistance of a wire in a series circuit, consisting only of 1 component (e.g. filament lamp) and a battery, is negligible; does each Coulomb of charge commit all of its electrical potential energy, supplied by the battery's potential difference, as work done across the component (thus electrical potential energy gained at battery = electrical potential energy lost across component)?
If so, how is voltage divided evenly across 2 identical components in series?
i.e. how do the circuit electrons give up only half their electrical potential energy at component 1, to 'save' some electrical potential energy for component 2?
If so, how is voltage divided evenly across 2 identical components in series?
i.e. how do the circuit electrons give up only half their electrical potential energy at component 1, to 'save' some electrical potential energy for component 2?
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