Exponential of a large negative number

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The discussion centers on calculating the exponential of a large negative number using the formula e-r = 10(-r log e). Participants clarify that the logarithm in the formula is indeed the natural logarithm (log e), and they emphasize that e raised to the zero power equals 1, while e raised to the first power equals e. The conversation also touches on the law of exponents, confirming that the interpretation of the logarithm does not change the fundamental properties of exponents.

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Aadrych
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Hi,

I read on a previous post that to calculate the exponential of a large negative number I use the formula:
e-r=10(-rloge)
This is just a quick question but it it meant to be a log 10 or natural log and also is it meant to be loge0 or loge1

Thanks in advance
 
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Aadrych said:
I read on a previous post that to calculate the exponential of a large negative number I use the formula:
e-r=10(-rloge)
This is just a quick question but it it meant to be a log 10 or natural log and also is it meant to be loge0 or loge1
What is e raised to the zero power? What is the natural log of that? What is the base 10 log of that? Would either interpretation make any sense?

What is e raised to the first power? What is the natural log of that? Would that interpretation make any sense?

Can you use the law of exponents, (ab)c = abc to derive the formula in question?
 
It should be obvious that if that were a natural logarithm, then ln(e) would be 1 and there would be no reason to write it!
I can see no reason to as if the "e" is e^0 or e^1. Any number, a, by itself, is a^1. Any number, including e, to the 0 power is 1.
 

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