Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Exponential simultaneous equation with powers

  1. Jun 1, 2010 #1
    Hi there,Struggling with this problem, anyone know how this might be solved?

    (e^(r-0.04)^(5/12))(0.9463) = (e^(r-0.04)^(11/12))(0.95152)

    and solve for r

    Ans: r~2.90%

    Would really appreciate it!
     
  2. jcsd
  3. Jun 1, 2010 #2

    Mark44

    Staff: Mentor

    It's hard to tell for certain what you're working with. Is this it?
    [tex]0.9463(e^{r - .04})^{5/12} = .95152(e^{r - .04})^{11/12}[/tex]

    If so, when you raise an exponent to a power, the exponents multiply, so the above can be rewritten as
    [tex]0.9463e^{(5/12)(r - .04)} = .95152e^{(11/12)(r - .04)}[/tex]

    Now take the natural log of both sides.
     
  4. Jun 2, 2010 #3
    Thank you Mark44.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook