Express as a single fraction n/(n-3) - n/(n+2)

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Homework Help Overview

The problem involves expressing the difference of two fractions, n/(n-3) and n/(n+2), as a single fraction. The subject area pertains to algebraic manipulation of rational expressions.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore numerical substitution to evaluate the expression, while others emphasize the need for a polynomial approach to combine the fractions. There is discussion about the correctness of the method used and the interpretation of the problem.

Discussion Status

The discussion includes various attempts to solve the problem, with some participants validating numerical results while others suggest a more algebraic method. There is no explicit consensus, but multiple perspectives on the approach are being explored.

Contextual Notes

Some participants question the appropriateness of using specific values for n, while others note that the expression can yield different results depending on the values chosen.

Gringo123
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n/(n-3) - n/(n+2)

I have tried to solve this by giving n a value. I chose n = 6, which gives:

6/3 - 6/8

The LCM of 3 and 8 is 24 so...

6/3 - 6/8 = 48/24 - 18/24 which gives 30/24

Final answer = 5/4

Is that the correct answer and have I used the correct method of solving the problem?
 
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Hi Gringo123! :smile:
Gringo123 said:
n/(n-3) - n/(n+2)

I have tried to solve this by giving n a value. I chose n = 6, which …

Sorry, but that's madness. :redface:

The question is asking for p(n)/q(n), where p and q are both polynomials in n.

(For example, 1/(n-1) + 1/(n+1) = 2n/(n2-1). :wink:)
 
Yes for n=6 your solution is correct. But n can take few more values to get a fraction.
 
I think I have it now
ans = 5n / (n-3)(n+2)
 
Yup! :biggrin:
 

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