Express dV/dt in terms of dr/dt - Derivative Word Problem

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Homework Help Overview

The problem involves expressing the rate of change of volume, dV/dt, in terms of the rate of change of radius, dr/dt, for a spherical weather balloon as air is pumped into it. The context is centered around the relationship between the volume of a sphere and its radius.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivative of the volume formula for a sphere and its implications for the rates of change. Some express uncertainty about their calculations and seek validation of their approach.

Discussion Status

Some participants have confirmed the correctness of the derivative obtained, while others have provided LaTeX representations of the equation. The discussion reflects a collaborative effort to clarify the mathematical reasoning involved.

Contextual Notes

There is a repeated emphasis on ensuring the correct application of calculus in the context of the problem, with participants questioning their understanding and the steps taken in their calculations.

bobraymund
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Homework Statement



Air is being pumped into a spherical weather balloon. At any time t, the volume of the balloon is V(t) and its radius is r(t).

Express dV/dt in terms of dr/dt.


2. The attempt at a solution

Volume of a Sphere = 4/3 pi r3

I took the derivative of the formula above and got:
3pir2_fracdrdt.gif


I ended up getting:
_LARGE__fracdVdt4pir2_fracdrdt.gif


Did I do this completely wrong? If so, what am I supposed to do?

Thanks,
Bob
 

Attachments

  • 3pir2_fracdrdt.gif
    3pir2_fracdrdt.gif
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You're right on the money.

In LaTeX script, your equation looks like this:
\frac{dV}{dt}~=~4\pi r^2 \frac{dr}{dt}

To see the script, click on the expression, and another browser window opens with the LaTeX script.
 
bobraymund said:

Homework Statement



Air is being pumped into a spherical weather balloon. At any time t, the volume of the balloon is V(t) and its radius is r(t).

Express dV/dt in terms of dr/dt.


2. The attempt at a solution

Volume of a Sphere = 4/3 pi r3

I took the derivative of the formula above and got:
3pir2_fracdrdt.gif


I ended up getting:
_LARGE__fracdVdt4pir2_fracdrdt.gif


Did I do this completely wrong? If so, what am I supposed to do?

Thanks,
Bob
I don't see anything at all wrong with it!
 
Thanks guys!

Mark44 said:
In LaTeX script, your equation looks like this:
\frac{dV}{dt}~=~4\pi r^2 \frac{dr}{dt}

To see the script, click on the expression, and another browser window opens with the LaTeX script.

Oh, thanks. I've been using a site called Texify to generate all these pictures! This will save a lot of my time in the future.

Thanks again,
Bob
 

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