Express Max height in terms of g and T? ?

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To express maximum height (y_max) in terms of gravitational acceleration (g) and time (T), the initial vertical velocity (V_0y) must be considered. The correct formula for height at time T is y = V_0y*T + 1/2gT^2, where V_0y is a constant. The maximum height occurs when the velocity reaches zero, indicating the object has stopped rising. It's crucial to ensure that the signs of V_0y and g are opposite, as V_0y should be positive while g is negative. Understanding these dynamics is essential for accurately calculating maximum height.
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Express Max height in terms of g and T?!?

I need to express the y_max in terms of g and T...

do i need to put in my V_0y value? or leave it as a variable?









i've tried V_0y*T + 1/2gT^2
 
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Vo is not a variable, it is constant. Your formula is correct for the height at time T. You have to find the time when the body reaches it maximum height and does not rise any more. What is its velocity at that instant?

ehild
 


Velocity at maximum height is 4.229 m/s
 


So it moves further upward. Why is it maximum height then?
Try to throw up something and watch the velocity.

And mind the signs. There is a maximum height if Vo points upward (and g downward) . Vo and g have to be of opposite signs. ehild
 
Last edited:
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