Expressing a series as a function

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The discussion revolves around expressing the series \(\sum \frac{x^{2n}}{n!}\) as a function, specifically identifying it as the Taylor series for \(e^{x^2}\). The original poster struggles with recalling how to express series as functions after a rushed calculus course. They seek alternative methods to derive the function without relying solely on memorized Taylor series expansions. Participants emphasize the importance of recognizing familiar Taylor series forms and suggest practicing differentiation and integration techniques. Ultimately, the conversation highlights the need for both memorization and understanding of series to effectively connect them to their corresponding functions.
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Homework Statement



I seem to have forgotten how to express a series as a function. I took calc 2 over the summer so we rushed through everything and i don't think all that information got a chance to settle. So here is the question. I'm going to try using syntax but i will write it out as well as this is the first time i use syntax.

If
\sum \frac{x^{2n}}{n!} = f(x) , then express f in terms of standard functions.

sum (n=0 to infinity) of (x^(2n)) / (n!)


Homework Equations






The Attempt at a Solution



No attempt, i don't even know where to start.
 
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taylor series .. ?

exponential.gif

http://www.efunda.com/math/taylor_series/exponential.cfm
 
Thank you, i now know which chapter to re-read. Greatly appreciated.
 
yup, looks like the Taylor series of exp(t) where t = x^2 :)
 
I can't seem to be able to come to the conclusion that you have gomunkul51 unless i follow the method used from the following site

http://www.cliffsnotes.com/study_guide/Taylor-Series.topicArticleId-19736,articleId-19727.html"

I know i should probably just stay quiet and deal with it, but is there any other way other than the one provided. Simply substituting the x^{2} in for x is easy but requires the memorization of the taylor series expansion of e^{x} I would prefer to be able to break it down using only the general taylor series formula. For example i tried the following:

f(x) = e^{x^{2}}
f ' (x) = 2xe^{x^{2}}
...
f^{(n)}(x) = 2^{n}x^{n}e^{x^{2}}

f(0) = 1
f ' (0) = 0
...
f^{(n)}(0) = ?

So using this method would be one way but it calls for f(x) to be chosen and becomes a guess and check deal if you don't have the experience with taylor series to be able to recognize the modified taylor series expansion of exp(x). My question: is it possible to go backwards from a taylor series to a function without the memorization that comes from experience dealing with common taylor series?

If not I appreciate your help.

P.S. Sorry for the sloppy syntax, I am not used to it.
 
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I advice you to memorize exp(x), sin(x), cos(x) and 1/(1-x) Taylor expansions they are everywhere! calculus, Complex Analysis...

You have to be able to recognize what the series looks like! this is the human approach :)
when you did recognized it look like some Taylor expansion you know, you can try to modify the original Taylor expansion like this: substitute x=f(t) or use differentiation and integration of the Taylor series.

What you tried to do with:
f(x) = <br /> e^{x^{2}}<br />

is trying to check if it is really equals to the series? because to do so you had to propose that you series equals to that function.

also you didn't differentiate correctly:
f(x) = exp(x^2)
f'(x) = 2x*exp(x^2)
f''(x) = 2exp(x^2) + 4x^2*exp(x^2)
...
 
Ok, thank you for your advice. I guess i will do a bunch of questions to drill it into my brain. I wrote down those taylor series before your reply because i kept seeing them online. Well, at least i only have to memorize 4. Again thank you.
 

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