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Expressing complex function in standard rectangular form

  1. Jan 27, 2009 #1
    I'm given a complex function in the exponential form:

    2.5j e^(-j40*pi)

    Transforming this into the standard Cartesian form is pretty straight forward, but the extra j multiplying the 2.5 is kind of throwing me off. I don't know if I did it right, but this is what I did:

    2.5j (cos[-40pi] + jsin[-40pi]) = 2.5j (cos[40pi] - jsin[40pi]) = 2.5j (1-0) = 2.5j

    Is that correct? I don't know if it is or not, because I don't see how you could transform it back into the original form after putting it into Cartesian form. Thanks
  2. jcsd
  3. Jan 27, 2009 #2


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    Staff: Mentor

    Looks right to me. Is there a way to check the answer?
  4. Jan 27, 2009 #3


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    Homework Helper
    Gold Member

    Yes that's correct :approve:

    If you are having difficulty transforming it into the original form, it is probably because the original form is not really the polar form.

    The polar form of 2.5j is 2.5e^(j*pi/2) but that is equivalent to the original expression since e^(-j*40pi)=e^0=1 (since the complex exponential has a period of 2pi).
  5. Jan 27, 2009 #4
    Ok good :)

    Such an odd question, I guess it was more or less to try and throw you off.
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