Expressing difference product using Vandermonde determinant.

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SUMMARY

The discussion centers on proving that the function \( g = g(x_1, x_2, \ldots, x_n) = (-1)^{n} V_{n-1}(x) \), where \( g(x_i) = \prod_{i PREREQUISITES

  • Understanding of Vandermonde determinants
  • Familiarity with polynomial functions and their properties
  • Knowledge of sigma notation and its applications in mathematics
  • Basic concepts of determinants in linear algebra
NEXT STEPS
  • Study the properties of Vandermonde determinants in detail
  • Learn about polynomial interpolation and its relation to determinants
  • Explore advanced techniques in linear algebra for determinant evaluation
  • Investigate the applications of determinants in solving systems of equations
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Mathematics students, educators, and researchers interested in algebraic structures, particularly those focusing on determinants and polynomial functions.

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Homework Statement


Show that ##g=g(x_1,x_2,...,x_n)=(-1)^{n}V_{n-1}(x)## where ##g(x_i)=\prod_{i<j} (x_i-x_j)##, ##x=x_n## and ##V_{n-1}## is the Vandermonde determinant defined by
##V_{n-1}(x)=\begin{vmatrix}
1 & 1 & ... & 1 & 1 \\
x_1 & x_2 & ... & x_{n-1} & x_n \\
{x_1}^2 & {x_2}^2 & ... & {x_{n-1}}^2 & {x_n}^2 \\
... & ... & ... & ... & ... \\
{x_1}^{n-1} & {x_2}^{n-1} & ... & {x_{n-1}}^{n-1} & {x_n}^{n-1}

\end{vmatrix}##

Homework Equations


N\A

The Attempt at a Solution


After expressing the determinant using the sigma notation I attempted to take a common factor to express it in a similar fashion but to no success. Other than that I really don't know how to approach this (I know I shouldn't say this but it is the case) as I never encountered a proof of this kind, and so I would appreciate some help.
 
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