(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A square loop with side-length a is positioned at the centre of a long thin solenoid, which has

radius r (with r > a), length l and N turns. The plane of the loop is perpendicular to the

5axis of the solenoid. A current I = I0 sin ωt ﬂows through the loop. Derive an expression for

the time-averaged power dissipated in a resistance R connected between the terminals of the

solenoid. You may assume that R is much greater than the resistance of the solenoid and

that the self-inductance of the solenoid is negligible.

2. Relevant equations

P = J E d (this is meant to be the integral of the total volume of the shape in question)

P = I^2 * R

3. The attempt at a solution

I understand how the power dissipated is calculated over a macroscopic object. But how does this change when it is the referring to a solenoid and the terminals?

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# Homework Help: Expression for the time average power dissipated in a resistance R

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