How is Max Power Transferred in a Circuit?

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SUMMARY

The maximum power transfer theorem states that maximum power is delivered to a load when the load resistance equals the internal resistance of the generator. In the discussed circuit, the Norton's equivalent resistance was calculated as 5.4Ω, and the short-circuit current through terminals AB was found to be 2.79A. However, the initial power calculation of 42.04W was incorrect because it did not account for the load resistance being equal to the equivalent resistance. The correct approach involves determining the current through the load resistance R when R equals the equivalent resistance.

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Homework Statement


Find the max power transferred through R in the circuit given.


Homework Equations



See attachment for the diagrams

The Attempt at a Solution



The Norton's equivalent resistance is 5.4Ω. For finding the Norton's current, I need to find the short-circuit current through the terminal AB.
Applying Kirchhoff's law to the middle loop, I can write
4(i-2)=1.43(5-i)
i=2.79

Thus, P = Inorton2Req = 42.04.
But this is the incorrect answer.
 

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The maximum power is transferred to a load equal to the internal resistance of the generator. You calculated the power supplied to the Norton resistance, if there was no load. How much current would flow through the loading resistance R if R=Req?

ehild
 
ehild said:
The maximum power is transferred to a load equal to the internal resistance of the generator. You calculated the power supplied to the Norton resistance, if there was no load. How much current would flow through the loading resistance R if R=Req?

ehild

Thanks! It solved my problem.
 

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