How is Max Power Transferred in a Circuit?

  • Thread starter utkarshakash
  • Start date
  • Tags Tags
    Max Power
2 replies · 2K views · last reply
utkarshakash
Gold Member
Messages
852
Reaction score
13

Homework Statement


Find the max power transferred through R in the circuit given.


Homework Equations



See attachment for the diagrams

The Attempt at a Solution



The Norton's equivalent resistance is 5.4Ω. For finding the Norton's current, I need to find the short-circuit current through the terminal AB.
Applying Kirchhoff's law to the middle loop, I can write
4(i-2)=1.43(5-i)
i=2.79

Thus, P = Inorton2Req = 42.04.
But this is the incorrect answer.
 
Attachments
  • Handwritten circuit schematic with a 5 A current source, resistors 5Ω, 2Ω, 4Ω and 1Ω, a resistor labelled R between nodes a and b, and a 2A current source on the right; caption reads 'the circuit in R'.
    elec_1.gif
    124 KB · Views: 651
  • Handwritten circuit schematic with a 5 A current source on the left, a 1.4 Ω resistor and a 4 Ω resistor in parallel branches, a 1 Ω resistor on top, and a 2 A current source on the right, with node labels a and b and branch currents 5-i, i-2 and i marked.
    elec_2.gif
    103.7 KB · Views: 609
The maximum power is transferred to a load equal to the internal resistance of the generator. You calculated the power supplied to the Norton resistance, if there was no load. How much current would flow through the loading resistance R if R=Req?

ehild
 
ehild said:
The maximum power is transferred to a load equal to the internal resistance of the generator. You calculated the power supplied to the Norton resistance, if there was no load. How much current would flow through the loading resistance R if R=Req?

ehild

Thanks! It solved my problem.