F(x) = x * sin(1/x) for x =/=0 and f(0) = 0. continuous on R?

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SUMMARY

The function f(x) = x * sin(1/x) for x ≠ 0 and f(0) = 0 is uniformly continuous on R. The domain of f is all real numbers, and the analysis shows that for any ε > 0, there exists a δ > 0 such that if |x - y| < δ, then |f(x) - f(y)| < ε. The function is continuous across R and exhibits a bounded derivative on the interval [-1, 1], confirming its uniform continuity.

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Homework Statement



Is the function f(x) = x * sin(1/x) for x =/= 0 and f(0) = 0 unifoirmly continuous on R?


Homework Equations





The Attempt at a Solution



dom(f) = (-inf, inf)



x,y in R and |x-y| < d imply |f(x) - f(y)| < e

|x - 0| < d imply |x * sin(1/x) - 0 | < e

?
 
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f is continuous on R, and it looks like it has a bounded derivative on R\[-1,1].
 

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