Factoring for Higher order ODE

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Homework Help Overview

The discussion revolves around solving a fifth-order differential equation, specifically focusing on finding the roots of the characteristic polynomial derived from the equation. The original poster expresses difficulty in factoring a fourth-degree polynomial to find complex roots after identifying one real root.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss methods for finding roots of a quartic polynomial, including using general formulas or guessing potential factors. There is also a mention of confusion regarding the constant term in the characteristic polynomial.

Discussion Status

The conversation includes various suggestions for tackling the polynomial, with some participants expressing skepticism about the practicality of certain methods. There is no explicit consensus on the best approach, but multiple strategies are being explored.

Contextual Notes

The original poster is preparing for a quiz on higher-order differential equations, raising concerns about the feasibility of solving complex polynomials by hand in an exam setting.

trap101
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Solve the differential equation:

y(5)+12y(4)+104y(3)+408y''+564y'=0

where the (n) is the nth derivative.

So it's a 5th order DE. Now I'm trying to find the roots:

One of the roots is r = 0, which I obtain by factoring the equation into this form:

r(r4+12r3+104r2+408r+1156) = 0

No problem there. Now the other solutions are complex, my issue is how can I find those solutions from this 4th degree polynomial? I can't synthetically divide like it was just real numbers, so what do I do? The solution get's it into the form:

(r2+6r+34)2 from here I see how to get the complex, but how do I factor my above equation even to get this equation?

Besides that factoring issue I understand the problem.

Thanks
 
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You can look up "roots of quartic" in wikipedia and use the general formula they supply or you just guess. (Or use a math program.)

Since it is a 4th order polynomial, not obviously a quadratic in r^2, you would guess something like (ar^2+br+c)^2 - expand it out and compare the coefficients.
 
In your characteristic polynomial, it is not clear why you have 1156 as the constant term rather than 564.
 
Simon Bridge said:
You can look up "roots of quartic" in wikipedia and use the general formula they supply or you just guess. (Or use a math program.)

Since it is a 4th order polynomial, not obviously a quadratic in r^2, you would guess something like (ar^2+br+c)^2 - expand it out and compare the coefficients.



LOL, using that formula is just a cruel joke. If that's the only way of being able to solve these sorts of problems. How would they ask them on a quiz? I ask because I have a quiz tomorrow and it is mainly on higher order DE's if this is the general format to get them, how in tarnation are they going to ask me to solve any higher order DE's beyond one's with real solutions? That would be a nightmare to solve by hand.
 
trap101 said:
LOL, using that formula is just a cruel joke. If that's the only way of being able to solve these sorts of problems. How would they ask them on a quiz? I ask because I have a quiz tomorrow and it is mainly on higher order DE's if this is the general format to get them, how in tarnation are they going to ask me to solve any higher order DE's beyond one's with real solutions? That would be a nightmare to solve by hand.

There are almost no practical uses for that formula. If they give you a high order polynomial to solve they will have set it up to be easy enough so it will factor with some guessing.
 

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