I Faraday's Law Equation: Derivative vs Delta

  • I
  • Thread starter Thread starter ManfredArcane
  • Start date Start date
  • Tags Tags
    Faraday's law Law
Click For Summary
The discussion centers on the two forms of Faraday's Law: ε=-(dΦB)/(dt) and ε=-(ΔΦB)/(Δt). The first equation represents the instantaneous rate of change of magnetic flux, while the second is an approximation used when the change is relatively constant over a time interval. Both forms are considered equivalent under specific conditions, particularly when the rate of change is stable. The approximation is useful for practical calculations in scenarios where precision is less critical. Understanding these nuances is essential for applying Faraday's Law effectively in physics.
ManfredArcane
Messages
3
Reaction score
1
My textbook gives the equation for Faraday's Law as ε=-(dΦB)/(dt) , the derivative of magnetic flux with respect to time. I have also seen Faraday's law expressed as ε= -(ΔΦB)/(Δt). Are these two forms equivalent? Thanks!
 
Physics news on Phys.org
You can take them equivalent.
 
The latter is an approximation to the former. It's only valid when the rate of change is constant, or close enough that you don't care.
 
I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...