Understanding Faraday's Law and the Significance of divB = 0

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SUMMARY

Faraday's Law is an independent law in electromagnetism, not a consequence of Coulomb's or Biot-Savart's laws. The divergence of the magnetic field, expressed as divB = 0, is derivable from the Biot-Savart law, but it is also valid in the context of magnetostatics. If magnetic monopoles were discovered, divB would no longer equal zero, necessitating the addition of a Coulomb-like term to the Biot-Savart law while still allowing it to describe the magnetic field generated by currents. The discussion highlights the interdependence of these fundamental laws in electromagnetism.

PREREQUISITES
  • Understanding of Maxwell's equations
  • Familiarity with Biot-Savart law
  • Knowledge of magnetostatics concepts
  • Basic principles of electromagnetism
NEXT STEPS
  • Study the derivation of Faraday's Law from Maxwell's equations
  • Explore the implications of magnetic monopoles on existing electromagnetic theories
  • Learn about the mathematical formulation of divB and its physical significance
  • Investigate the relationship between curlB and current density (j) in electromagnetism
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Students of physics, educators in electromagnetism, and researchers exploring advanced concepts in electromagnetic theory.

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I'm reading a book on electromagnetism and I am a bit confused about some things in Maxwells equations. This is what I don't like about many physics books: they are very wordy, but at the end you don't know what is an experimental fact, what is a "theorem", what is an assumption and so on,...

Anyway the questions are:

1. Is Faraday's law a consequence of Coulomb's and Biot-Savart's (or Ampere's) law?

2. Is divB = 0 consequence of Biot-Savart's law i.e. if we found the magnetic monopole, would that mean that Biot-Savart's law is not true? (I think so, but I am not 100% sure)
 
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1. No, it is a new law, not envisioned by Coulomb, Biot, Savart, nor even Farady until he discovered it.
2. divB=0 is derivable from the B-S law. and was originally found that way,
but one can start the study of magnetostatics with divB=0 and curlB~j and derive B-S. The two laws are compatible, each derivable from the other.
If a magpole exists, then divB is no longer zero and a Coulomb-like term would have to be added to B-S, but B-S would still give the B field of a current. What EM book are you reading?
 

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