Ferris Wheel - Trigonometric Function

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SUMMARY

The discussion focuses on the mathematical modeling of a pendulum ride at Canada's Wonderland using trigonometric functions. The height of the rider is analyzed over time, leading to the determination of amplitude (25 m), vertical translation (30 m), and the calculation of the period (28 seconds) using the formula for sine functions. The user encountered confusion regarding the relationship between radians and degrees in calculating the period, specifically the use of 2π versus 360 degrees. The final equation derived is y=25sin[12.86(x-1.92)]+30, which the user found did not match their graphing software output.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine functions
  • Knowledge of amplitude and vertical translation in wave functions
  • Familiarity with the concept of period in trigonometric functions
  • Ability to convert between radians and degrees in mathematical calculations
NEXT STEPS
  • Learn how to graph trigonometric functions using software tools like Desmos or GeoGebra
  • Study the effects of phase shifts on sine and cosine functions
  • Explore the relationship between radians and degrees in trigonometric calculations
  • Investigate the properties of pendulum motion and its mathematical modeling
USEFUL FOR

Students studying trigonometry, educators teaching mathematical modeling, and anyone interested in the physics of pendulum motion and its representation through trigonometric functions.

Sabellic
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Pendulum Ride - Trigonometric Function

Homework Statement


At Canada's Wonderland, a thrill seeker can ride the Xtreme Skyflyer. This is essentially a large pendulum of which the rider is the bob. The height of the rider is given for various times:

Time(s) 0 1 2 3 4 5 6 7 8 9
Height(m) 55 53 46 36 25 14 7 5 8 15

Find the amplitude, period, vertical translation, and phase shift for this function. [Note: that the table does not follow the bob through one complete cycle, s

Homework Equations


y=a sin [b(x-c)] + d


The Attempt at a Solution



To find "a" (amplitude)= (max - min) / 2 = (55 - 5)/2 = 25
To find "d" (axis of symmetry)= (max + min) / 2 = (55 + 5)/2 = 30

To find "b" find the Period

Period = 2p/absolute value of b

However, because this ride works as a pendulum, one cycle will be completed when there are 2 highs and 2 lows. So the bob starts at a height of 55 metres; it will then reach a low of 5 metres; it will (hypothetically) reach a height until it runs out of speed; it will then (hypothetically) return to the minimum height of 5 metres; and then, finally it will return to its start position. That is the completion of 1 cycle in a pendulum.

Because the graph is incomplete, we have just one maximum and one minimum. The maximum starts at 55 metres, and then there is a minimum at 5 metres. Therefore, we have only completed 1/4 of the cycle at 7 seconds. Roughly, a complete cycle will take 28 seconds.

Therefore Period= 2pie/b

which becomes:
28 seconds = 2pie/b
28=360/b
b=360/28
b=12.86

So the "b" value is 12.86.


To find the value of "c", I will plug in a co-ordinate value into the equation. Let us take the co-ordinate (3, 36)

Therefore:
y=asin[b(x-c)]+d; becomes:

36=25sin[12.86(3-c)]+30
6=25sin[12.86(3-c)]
6/25=sin[12.86(3-c)]
13.89=12.86(3-c)
1.08=3-c
c=3-1.08
c=1.92

And so, my final equation reads as:

y=25sin[12.86(x-1.92)]+30

However, when I enter this value into my graphing software, it looks nothing like the graph I did on paper! Do you guys see any errors in what I did?

Thank you so much in advance.
 
Last edited:
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Therefore Period= 2pie/b

which becomes:
28 seconds = 2pie/b
28=360/b
b=360/28
b=12.86
You have replaced 2*pi with 360. While it's true that 2*pi radians is the same angle as 360 degrees, it's not true that 2*pi = 360.
 
Mark44 said:
You have replaced 2*pi with 360. While it's true that 2*pi radians is the same angle as 360 degrees, it's not true that 2*pi = 360.

I don't understand. My teacher said that The period of the graphs on transformed sine and cosine functions can be found by the following formula: 2pi/|b|.

As well, whenever I did my previous questions using 360/|b| I got the correct answer.:confused:
 
Sabellic said:
I don't understand. My teacher said that The period of the graphs on transformed sine and cosine functions can be found by the following formula: 2pi/|b|.

As well, whenever I did my previous questions using 360/|b| I got the correct answer.:confused:
If you're doing calculations with a calculator in degree mode, that will work. It won't work if the calculator is in radian mode.

Just think about it: pi is about 6.28, which is nowhere near 360, But pi radians is the same angle measure as 360 degrees.
 
Mark44 said:
If you're doing calculations with a calculator in degree mode, that will work. It won't work if the calculator is in radian mode.

Just think about it: pi is about 6.28, which is nowhere near 360, But pi radians is the same angle measure as 360 degrees.
Typo alert: 2 pi radians is the same angle measure as 360 degrees.
 
HallsofIvy said:
Typo alert: 2 pi radians is the same angle measure as 360 degrees.
Thanks, Halls. I actually had a factor of 2 in there momentarily and took it out.
 

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