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My textbook says that if you are on a ferris wheel that is rotating, the total work done by all the forces acting on your is zero. How is that possible? You are moving so isn't work being done to you?
Assuming ferris wheel is moving at constant speed ,the net force acting on the body will be centripetal (i.e towards the center) .The velocity of the body at any instant is tangential .Since the velocity and the force are orthogonal(perpendicular) to each other ,the net work done given by ∫F.ds will be zero.My textbook says that if you are on a ferris wheel that is rotating, the total work done by all the forces acting on your is zero. How is that possible? You are moving so isn't work being done to you?
The reasoning is incorrect ...Yes, but when the ferris wheel stops and you get off, you are in the same place that you started, the net displacement is 0, so the net work done is 0. For the first half of the turn, the ferris wheel will do some work on you, but the second half, it will do the exact same amount of negative work, cancelling out the original work it did.
The person in a ferris wheel starts from rest and gradually acquires a speed .Till the time the person starts moving with the constant speed ,work will be done .Why ? because there will be a tangential force increasing the speed of person .Since there is a force(tangential) in the direction of displacement(tangential),work will be done.So if there is a change in kinetic energy wouldn't that mean that there IS work done...?
Force and direction of motion will be orthogonal , when the person is moving with a constant speed.There is no contradiction in what i have said.And yet you said that the direction of motion and the force are orthogonal and therefore the work done is zero..?
hey PsychonautQQ!!!My textbook says that if you are on a ferris wheel that is rotating, the total work done by all the forces acting on your is zero. How is that possible? You are moving so isn't work being done to you?