At a particular moment, three small charged balls, one negative and two positive,are located as shown in the figure. q1 = 3 nC, q2 = 7 nC, and q3 = -5 nC.
What is the electric field at the location of Q1, due to Q2?
Okay that is the given diagram the if q2 is at (0,0) then q1 is at (0,4); q3 at (3,0);
and the distances are in centimeters
I'm using Coulomb's Law which states that E = 9e9*(q/r^2)r-hat
The Attempt at a Solution
So I thought all I have to do is plug in the values
[9e9*(7e-9/(.004)^2)]*<0,4,0> = <0,3937500,0>N/C
please help me, I've been starring at this for a while and I cannot figure out why I don't get the right answer, I shouldn't have to consider the other charges because they don't affect the field created by q2 just the net field, so why is this not correct I have no idea.
Thanks Again for all the help guys