Field and force with three charges

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Homework Help Overview

The problem involves calculating the electric field at the location of one charge (q1) due to another charge (q2) in a system with three charges: one negative and two positive. The charges are given specific values and positions, and the context includes the use of Coulomb's Law for the calculation.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply Coulomb's Law to find the electric field due to q2 at the location of q1 but encounters difficulties with unit conversion and the application of the formula.

Discussion Status

Participants are engaged in clarifying the units of measurement and addressing the original poster's confusion regarding unit conversion from centimeters to meters. Some guidance has been provided regarding the correct use of unit vectors in the calculation.

Contextual Notes

There is a noted issue with unit conversion, as the original poster mistakenly converted centimeters to meters. The discussion also highlights the assumption that only the charge q2 affects the electric field at the location of q1, without considering the influence of the other charge (q3).

Squall
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Homework Statement



At a particular moment, three small charged balls, one negative and two positive,are located as shown in the figure. q1 = 3 nC, q2 = 7 nC, and q3 = -5 nC.

What is the electric field at the location of Q1, due to Q2?

y
q1
|
|
|
q2______q3____x

Okay that is the given diagram the if q2 is at (0,0) then q1 is at (0,4); q3 at (3,0);
and the distances are in centimeters

Homework Equations



I'm using Coulomb's Law which states that E = 9e9*(q/r^2)r-hat

The Attempt at a Solution



So I thought all I have to do is plug in the values

[9e9*(7e-9/(.004)^2)]*<0,4,0> = <0,3937500,0>N/C

please help me, I've been staring at this for a while and I cannot figure out why I don't get the right answer, I shouldn't have to consider the other charges because they don't affect the field created by q2 just the net field, so why is this not correct I have no idea.

Thanks Again for all the help guys
 
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In what units are the components of the position?

ehild
 
The components of the positions are in centimeters. (cm)
 
If so, 4 cm = 0.04 m. And you have to use the unit vector in the direction of <0,4,0>.

ehild
 
Oh yes your right, I just kept converting the cm to m wrong, putting an extra zero in front of it like they were mm or something. Thank You so much it really helps having someone else look at this. I knew I had to be making some stupid mistake.
 

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