find the final temperature of A 150g (0,15kg) cube of ice at 0.0 degrees Celsius is added to 300g(0.3 kg) of water at 50.0 degrees Celsius.
Specific heat capacity of ice: 2.09 x 10^3 J/(kg x degrees Celsius)
Specific heat capacity of water: 4.186 x 10^3 J/(kg x degrees Celsius)
Q = m x L
energy transferred as heat during a phase change = mass x latent heat
Q = m Cp deltaT
energy transferred as heat = mass x specific heat capacity x change in temperature
The Attempt at a Solution
I wouldnt had problem to solve if it wasnt for the phase change
For the water q=mcdeltaT
If it was no phase its the same for the other liquid and then just set them equal to = 0 and find the T but no with the Phase it will be a bit different but how ?