Final temperature - Thermodynamics problem

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SUMMARY

The discussion focuses on calculating the final temperature when a 2kg frying pan at 70°C is placed into a bowl of 4kg water at 20°C. The relevant formula used is E = mcΔT, where 'm' represents mass, 'c' is heat capacity, and 'ΔT' is the temperature change. The heat lost by the frying pan equals the heat gained by the water, leading to the equation 50 = ΔT_P + ΔT_W, which is essential for solving the problem. The final temperature can be determined by applying the principle of energy conservation.

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  • Ability to set up and solve algebraic equations involving temperature changes.
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1. A frying pan, weighing 2kg (heat capacity = 490 J/kg/K) and at a temperature of 70C is plunged into a bowl containing 4kg of water (heat capacity = 4200) at 20C. Assuming the bowl has negligible heat capacity and assuming that there is no heat flow to or from the surroundings, what is the final temperature of the water in the bowl to the nearest C?
2. E = mcΔT, where m is mass, c is heat capacity and T is the temperature
3. 50 = ΔT_P + Δ T_W [/b], where the first term is the temperature change of the pan and the second term is the temperature change of water. But I don't know how to continue this problem.
 
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Suppose that the two materials end up at some common final temperature between the two starting temperatures. Write expressions for the heat lost by the one that's cooling, and heat gained by the one that's warming. Then apply energy conservation...
 

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