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When a ball of mass 180 g is struck by a bat moving in the opposite direction,
the force acting on the ball is as shown in the graph (Figure 8.37). Determine
The final velocity of the ball if it was initially moving at
10.0 m s–1 south.
The graph depicted the Impulse as 10Ns (I checked the textbook and it was right)
However, when I calculated the final velocity, I got 65.55 and the answer in the textbook was 45.555
Ft = m(v-u)
10 = 0.180(v-10)
65.55 = v
Unless the Impulse is equation is Ft = m(u-v), i don't know how I got the answer wrong...
the force acting on the ball is as shown in the graph (Figure 8.37). Determine
The final velocity of the ball if it was initially moving at
10.0 m s–1 south.
The graph depicted the Impulse as 10Ns (I checked the textbook and it was right)
However, when I calculated the final velocity, I got 65.55 and the answer in the textbook was 45.555
Ft = m(v-u)
10 = 0.180(v-10)
65.55 = v
Unless the Impulse is equation is Ft = m(u-v), i don't know how I got the answer wrong...