Velocity Calculation of Kicked Rugby Ball

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Homework Help Overview

The discussion revolves around calculating the velocity of a rugby ball 3.0 seconds after it is kicked vertically upwards with an initial speed of 16 m/s. The problem involves concepts from kinematics, specifically the equations of motion under uniform acceleration due to gravity.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to apply the SUVAT equations to find the final velocity, questioning the signs of acceleration and the direction of motion. There are discussions about the displacement and the effects of gravity on the ball's motion, including considerations of when the ball reaches its peak height and begins to descend.

Discussion Status

Several participants share their calculations and reasoning, noting mistakes and corrections along the way. There is acknowledgment of the complexity of the problem, with some participants suggesting that the ball's velocity changes as it rises and falls within the given time frame. Guidance is offered regarding the importance of considering the direction of acceleration.

Contextual Notes

Participants express confusion over the application of formulas and the implications of the ball's vertical motion, particularly regarding the point at which the ball's velocity becomes zero and its subsequent behavior. There is a recognition of the need to clarify the timing of these events without resolving the calculations.

Rumplestiltskin
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Homework Statement


What is the velocity of a rugby ball 3.0s after it is kicked vertically upwards with a speed of 16m/s? Give your answer to 2 s.f.

Homework Equations


SUVAT

The Attempt at a Solution


s = ?
u = 16
v = ?
a = g = 9.8
t = 3

Erm... v = u + at?
16 + 9.8 x 3 = 45m/s. Incorrect, try again.
...aha! Ball was kicked vertically up. Acceleration is going to be acting against. Not today, physics!
16 - 9.8 x 3 = -13m/s. Incorrect, try again.
Huh. Well, it might be a case of direction. Let's try plain 13m/s. Incorrect, try again.
Okay, let's work out the displacement so we can try v = √2gs. s = 16 x 3 - 0.5 x 9.8 x 3^2 = 3.9m. Nice round number! Must be on to something.
v = √2 x 9.8 x 3.9 = 8.7m/s. Incorrect, try again.
Wait, I'm a doughnut. That's just for free fall. I have a u value. So it's going to be v = √u^2 + 2as.
√16^2 + 2 x 9.8 x 3.9 = 18m/s. Incorrect, try again.
Uh. Oh, g would still be negative. This has got to do it.
√16^2 - 2 x 9.8 x 3.9 = 13m/s. I'm done. SOS.
 
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Rumplestiltskin said:
...aha! Ball was kicked vertically up. Acceleration is going to be acting against. Not today, physics!
16 - 9.8 x 3 = -13m/s. Incorrect, try again.
Looks right to me.
 
Rumplestiltskin said:

Homework Statement


What is the velocity of a rugby ball 3.0s after it is kicked vertically upwards with a speed of 16m/s? Give your answer to 2 s.f.

Homework Equations


SUVAT

The Attempt at a Solution


s = ?
u = 16
v = ?
a = g = 9.8
t = 3

Erm... v = u + at?
16 + 9.8 x 3 = 45m/s. Incorrect, try again.
...aha! Ball was kicked vertically up. Acceleration is going to be acting against. Not today, physics!
16 - 9.8 x 3 = -13m/s. Incorrect, try again.
Huh. Well, it might be a case of direction. Let's try plain 13m/s. Incorrect, try again.
Okay, let's work out the displacement so we can try v = √2gs. s = 16 x 3 - 0.5 x 9.8 x 3^2 = 3.9m. Nice round number! Must be on to something.
v = √2 x 9.8 x 3.9 = 8.7m/s. Incorrect, try again.
Wait, I'm a doughnut. That's just for free fall. I have a u value. So it's going to be v = √u^2 + 2as.
√16^2 + 2 x 9.8 x 3.9 = 18m/s. Incorrect, try again.
Uh. Oh, g would still be negative. This has got to do it.
√16^2 - 2 x 9.8 x 3.9 = 13m/s. I'm done. SOS.
This is what happens when you throw a bunch of formulas at a problem before thinking it through.

Even rugby balls kicked vertically upward can only rise so high.

What happens when the kicked ball goes up and then starts to come back down within this 3 second interval?
 
SteamKing said:
This is what happens when you throw a bunch of formulas at a problem before thinking it through.

Even rugby balls kicked vertically upward can only rise so high.

What happens when the kicked ball goes up and then starts to come back down within this 3 second interval?

Noted.

The velocity reaches 0, and then rises again. How do I tell what point it's at? Could still be rising.
 
Rumplestiltskin said:
The velocity reaches 0, and then rises again. How do I tell what point it's at?
You don't need to where this occurs, just when it occurs.
 
haruspex said:
Looks right to me.

Huh... just retried and it was accepted this time. That was a headache. Thanks!
 

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