Find a function from a given derivative

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SUMMARY

The discussion centers on finding a function F such that F(2) = 0 and F'(x) = sin(e^x). The correct approach involves applying the Fundamental Theorem of Calculus (FTC), specifically FTC II, which states that F(x) can be expressed as F(x) = ∫ from 2 to x of sin(e^t) dt. This formulation satisfies both the derivative condition and the initial condition F(2) = 0, confirming its correctness.

PREREQUISITES
  • Fundamental Theorem of Calculus (FTC)
  • Integration techniques for trigonometric functions
  • Understanding of antiderivatives
  • Basic knowledge of exponential functions
NEXT STEPS
  • Study the Fundamental Theorem of Calculus in detail
  • Practice integration of functions involving exponential and trigonometric components
  • Explore techniques for evaluating definite integrals
  • Learn about the properties of antiderivatives and their applications
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Students studying calculus, particularly those focusing on integration and the Fundamental Theorem of Calculus, as well as educators seeking to clarify these concepts for their students.

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Homework Statement


Find a function F such that F(2) = 0 and F'(x) = sin(e^x)

I think that this a reverse to Part 2 of the Fundamental Theorem of Calc but not really sure.

Homework Equations


From the Theorem:
A(x) = [tex]\int f(t) dt[/tex]

A'(x) = f(x)

f(t) = sin(e^x) ??


The Attempt at a Solution


I attempt to integrate sin(e^x) but that seems like a lost cause.

According to FTC II, the area function with lower limit a=2 is an antiderivative satisfying
F(2) = 0

F(x) = [tex]\int^{x}_{2} sin(e^t)dt[/tex]

Is this the correct function
 
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That works fine.
 

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