Find a number that is algebraic with degree 3 over Z_3

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SUMMARY

To find a number that is algebraic with degree 3 over Z_3, one must identify an appropriate extension field of Z_3. The algebraic closure of Z_3 is suggested as a potential solution, although its constructiveness is questioned. It is established that for any extension field E and number α, there exists a mapping π from the polynomial ring (\mathbb{Z} / 3\mathbb{Z})[t] to E such that π(t) equals α.

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Homework Statement


I want to find a number that is algebraic with degree 3 over Z_3. To do this, I need to find an extension field of Z_3. Q,R, and Z_p (p greater than 3) definitely will not work because they have different algebra. Anyone?

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ehrenfest said:

Homework Statement


I want to find a number that is algebraic with degree 3 over Z_3. To do this, I need to find an extension field of Z_3. Q,R, and Z_p (p greater than 3) definitely will not work because they have different algebra. Anyone?
How about the algebraic closure of Z_3? Or is that too nonconstructuve?

Well, at least we know that no matter what extension field E you use and number \alpha you select, there has to be a map \pi : (\mathbb{Z} / 3\mathbb{Z})[t] \to E with \pi(t) = \alpha.
 
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