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Introductory Physics Homework Help
Find acceleration of a box given the forces on it....
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[QUOTE="Simon Bridge, post: 5621896, member: 367532"] Note: ##\sum\vec F = m\vec a = (mg)\vec a/g \implies \vec a/g = \frac{1}{mg}\sum\vec F## ... ie. the net force divided by the weight is the acceleration in gees. ie. your answer would have been a = 0.14g. Then, no need to do that 1st division risking a possible rounding error. I bring this up because your reasoning seems fine - so the error will be in arithmetic or rounding off or something like that... or a mistake in the problem itself. So redo from the start... Info: W=895N, F=397N, ##\theta##=21deg, ##\mu##=0.24 ... the task is to derive an equation for the acceleration in terms of just these 4 things. Off free body diagram ##\sum\vec F = m\vec a## : (1) ##F\cos\theta - \mu N = ma = (W/g)a## since ##W=mg## (2) ##N-W-F\sin\theta = 0## (N=normal force) Do all the algebra first - when you have derived the final equatio, [I]then[/I] you can put the numerical values in. [/QUOTE]
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Find acceleration of a box given the forces on it....
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