- #1

Vibhor

- 971

- 40

## Homework Statement

[/B]

In the attached picture, the rope is being pulled by a constant force T. All the surfaces are smooth. The pulley and the rope are massless and frictionless. Find the acceleration of the wedge.(use g=10ms

^{-2})

## Homework Equations

## The Attempt at a Solution

The normal force between the block and wedge is represented by N and acceleration of the wedge by 'a'.

Writing ∑F = Ma for the wedge in horizontal direction , ##Nsinθ + Tcosθ -T = Ma## .

Resolving forces on the block in direction perpendicular to the surface of wedge , ##N=mgcosθ##

Using the above two equations , a = ##\frac{mgcosθsinθ + Tcosθ -T}{M}## .

This gives a = 2.28ms

^{-2}towards left. But the answer given is 1.3ms

^{-2}.

Could somebody help me identify the mistake .

Thanks