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## Homework Statement

Find an equation of the tangent line to the curve y = x√x that is parallel to the line

y = 1+3x.

## Homework Equations

m = 3

## The Attempt at a Solution

Here is my attempt: dy/dx(x) * dy/dx(x^(1/2)) = (1) * (1/2x^(-1/2)) = (1/2x^(-1/2))

(1/2x^(-1/2)) = 3 → x^(-1/2) = 6 → -√x = 6

x = -√36 = 6 → -6=6 -1=1

Thank you, I will not be able to respond for a bit as im leaving for home now.