Find Angle (theta) Given Displacement & Aircraft Velocity

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Homework Help Overview

The problem involves a dive bomber releasing a bomb from a certain altitude and determining the angle (theta) of the aircraft's velocity relative to the horizontal, given the displacement to the target on the ground.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for time to solve for the angle and question whether it can be derived from the given information. Some suggest focusing on the vertical motion while others express uncertainty about the horizontal component of the velocity affecting the time calculation.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the time to reach the ground, but there is no clear consensus on how to proceed due to the complexity of the situation.

Contextual Notes

There is uncertainty regarding the assumptions about the horizontal and vertical components of the motion, and the lack of explicit time information is a point of contention among participants.

integra2k20
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A dive bomber has a velocity of 275 m/s at an angle (theta) below the horizontal. When the altitude of the aircraft is 2.15 km, it releases a bomb, which subsequently hits a target on the ground. The magnitude of the displacement from the point of release of the bomb to the target is 3.45 km. Find the angle (theta).

OK, I'm not seeing a way to solve this without being given the time (t) it took for it to hit the ground, am i missing something here?
 
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You know the time. If it is released from 2.15 km, and it is subject to g, simply figure out how long it takes to reach the ground. Ignore the horizontal portion for now.
 
civil_dude said:
You know the time. If it is released from 2.15 km, and it is subject to g, simply figure out how long it takes to reach the ground. Ignore the horizontal portion for now.

but the plane's velocity isn't horizontal...therefore, the time to reach the ground can't be solved...
 
i asked my teacher about this today, he couldn't figure it out either...
 
2.3 degrees or 78 degrees?
like civil said,it can be calculated..just check again.
 

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