Find angular acceleration of a yoyo

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The discussion revolves around calculating the angular acceleration of a yo-yo as it unwinds while falling. The user sets up the equations for torque and moment of inertia, noting the contributions from the tension in the string and gravitational forces. Confusion arises regarding the roles of the different radii and whether linear acceleration should factor into the angular acceleration calculation. Ultimately, the derived equation for angular acceleration is presented as 4gr/R^2, leading to a consideration of the implications if the axle radius were zero. The conversation emphasizes the importance of understanding the relationship between linear and angular motion in this context.
Raziel2701
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Homework Statement


A Yo-Yo is made up of twp solid disks each with radius R and mass M. The axle has radius r and is essentially massless. The Yo Yo is released to unwind.
Find the angular acceleration of the YoYO as it falls in terms of r, R and g.


Homework Equations


\Sigma\tau=I\alpha

I = 1/2MR^2

I set up the sum of torques to be the tension from the string times r, plus 2MgR, though I don't see what difference there would be if it were 2Mgr:

\Sigma\tau=Tr +2MgR=I\alpha

I setup the following too:

\Sigma\F_y = T -2Mg = 2Ma To solve for T and substitute into my equation for the sum of torques.

Then solving for \alpha I finally get:

\frac{g(r+R) + ar}{R^2} I don't think my answer should have a term for linear acceleration, unless it's gravity too?

I feel like I'm doing things blindly. I know that the sum of torques should equal the moment of inertia times the angular acceleration, but this business with the different radii is confusing me and I am uncertain as to whether or not what I'm doing makes sense.

UNRELATED: I tried previewing the post after doing some modifications and it shows all out of formatting. Please excuse any oddities.
 
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I think I read too much into the problem. If the yo yo is falling, given the context of the problem there is no mention or too much emphasis on the string being unwounded, so I know that it's rotating but there's nothing to lead me to believe that there's a tension.

So setting up the sum of torques I get:

\Sigma\tau=2Mgr=I\alpha

Solving for alpha I get

4gr/R^2

Still, does this result make sense? I don't really have a way of checking my answer since this homework is just something we turn in. So, I was wondering, if r, the axle was very small, say even zero, then there would be no angular acceleration for the yoyo wouldn't rotate right?

So at least the equation makes sense that way I suppose?
 
If there was no tension there would be no torque and no angular acceleration...you had the right idea above, you just need the relationship between linear acceleration and angular acceleration.
 
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