Find angular momentum, energy, and distance of closest approach

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Homework Help Overview

The problem involves a particle moving in the xy plane under a repulsive central force that varies with distance. The initial conditions specify the particle's position and velocity, and the tasks include calculating energy and angular momentum, as well as determining the distance of closest approach to the origin.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of energy and angular momentum as the particle moves. There are questions about whether to calculate energy at the initial state or in a more general sense. Some participants explore the implications of the particle's trajectory and the nature of the force acting on it.

Discussion Status

Participants are actively engaging with the problem, raising questions about the relationships between energy, angular momentum, and the particle's motion. Some have suggested using conservation laws to relate quantities at different points in the trajectory, while others are considering the implications of approximations in their calculations.

Contextual Notes

There is an emphasis on the particle's behavior as it transitions from kinetic to potential energy within the force field. The discussion includes considerations of the particle's path and the nature of the force, which may affect the calculations of energy and angular momentum.

  • #31
oddjobmj said:
I like the initial simplification.

r=\frac{R}{2sqrt(1-AR_0)}

I believe that should be $$r = \frac{R_0}{2\sqrt{1-\frac{AR_0}{mw^2}}}$$
With the approximation of the square root, you have $$r = \frac{R_0}{2}(1+\frac{AR_0}{2mw^2})$$

I am comfortable now with the concepts that were touched on and this is how I would/will work out the problem. I must admit, though, that the further simplification for small x is something I would not likely use unless necessary.

Thank you for your advice and guidance!

OK. Good work.
 

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