Find angular momentum, energy, and distance of closest approach

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SUMMARY

The discussion focuses on calculating the energy, angular momentum, and distance of closest approach for a particle influenced by a repulsive central force defined by F(r)={A\hat{r} if rR0}. The particle's initial conditions are given as x=-3 R0, y=0.5 R0, Vx=w, and Vy=0. Energy is expressed as E = \frac{1}{2}mw^2, while angular momentum is represented as L = mw\alpha R0 sin(\theta). The participants conclude that both energy and angular momentum are conserved, and they explore the implications of these conservation laws to derive the distance of closest approach, emphasizing the need for first-order approximations in terms of A.

PREREQUISITES
  • Understanding of classical mechanics, specifically conservation laws.
  • Familiarity with angular momentum calculations in polar coordinates.
  • Knowledge of potential and kinetic energy relationships.
  • Ability to perform approximations in physics problems.
NEXT STEPS
  • Study the conservation of angular momentum in central force problems.
  • Learn about potential energy in the context of repulsive forces.
  • Investigate first-order approximations in physics for small perturbations.
  • Explore the relationship between energy and angular momentum in orbital mechanics.
USEFUL FOR

Students and educators in physics, particularly those focusing on classical mechanics and dynamics involving central forces, as well as anyone interested in problem-solving techniques for energy and angular momentum calculations.

  • #31
oddjobmj said:
I like the initial simplification.

r=\frac{R}{2sqrt(1-AR_0)}

I believe that should be $$r = \frac{R_0}{2\sqrt{1-\frac{AR_0}{mw^2}}}$$
With the approximation of the square root, you have $$r = \frac{R_0}{2}(1+\frac{AR_0}{2mw^2})$$

I am comfortable now with the concepts that were touched on and this is how I would/will work out the problem. I must admit, though, that the further simplification for small x is something I would not likely use unless necessary.

Thank you for your advice and guidance!

OK. Good work.
 

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