Find Angular Velocity of Centrifuge with Particle 10.0 cm Away

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SUMMARY

The discussion focuses on calculating the angular velocity of a centrifuge with a particle located 10.0 cm from the axis of rotation, which experiences a radial acceleration of 1.00 x 10^3 times the gravitational acceleration (g). The correct formula used is ar = r * w^2, leading to the calculation of angular velocity (w) as 313 rad/sec. The user initially miscalculated the radius, confusing 10.0 cm with 0.1 m instead of 0.01 m, which led to an incorrect interpretation of the results.

PREREQUISITES
  • Understanding of radial acceleration in rotational motion
  • Familiarity with angular velocity calculations
  • Knowledge of gravitational acceleration (g = 9.80 m/s²)
  • Basic algebra for manipulating equations
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  • Learn about the relationship between linear and angular quantities
  • Explore the effects of radius on centrifugal force
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This discussion is beneficial for physics students, engineers, and anyone involved in mechanical systems or rotational dynamics, particularly those working with centrifuges and related calculations.

Miike012
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A centrifuge is used to increase the sedimentation rate of
particles suspended in a liquid, over the rate produced
by gravity alone. Find the angular velocity of a centri -
fuge in which a particle 10.0 cm from the axis of rotation
experiences a radial acceleration of 1.00* 10^3
times gravitational acceleration g.

Solution: radius (r) = 0.01 m ; ar = 1.00*10^3*9.80


1.00*10^3*9.80 = (.01)w^2

w = ( 1.00*10^3*9.80/.01)^(1/2) = 989

Answer is 313 rad/sec...

where did I go wrong>?
 
Physics news on Phys.org
10.0 cm = 0.1 m

Do not underestimate the girth of the centimeter.
 
thank you,
 

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