60kg block slides along the top of 100kg block. 60kg block has an acceleration = 3.0m/s^2 while a horizontal force of 320N is applied to it. There is no friction between the 100kg block and the frictionless surface but there is friction between the two block. Find the coefficient of kinetic friction between the blocks
coefficient of kinetic friction = fk / Fn
The Attempt at a Solution
Well since the normal force is easy to find, Fn=ma (right?) and the fk I was thinking could be found by with mg...but when I divide ma/mg I get an answer that's just a little higher than the right answer (.306m/s^2 vs. .24m/s^2)
I feel like I might just be missing a simple step somewhere or confusing something, any insight on this would be much appreciated.