Find Current I3 in Circuit - Homework Statement

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To find the current I3 in the circuit, the user notes that the voltage across resistors R1 and R2 is the same, and the total current I0 is 12mA, which equals the sum of currents I1 and I2. The user sets up the equation relating the currents through the resistors, but realizes there may be an error in their calculations. They calculate I1 as 2.86mA but express uncertainty about the correctness of their approach. The discussion also raises the question of whether I2 is the sum of currents I3 and I4.
Gauss M.D.
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Homework Statement



Find the current marked I3 in the circuit.

Homework Equations





The Attempt at a Solution



The voltage over R2 and R1 is the same. The current I0 (12mA) is the sum of I2 and I1.

I1*R1 = I2*R2:
4*I1 = 1.25*I2

I1 + I2 = 12 <=> I2 = 12 - I1

4*I1 = 1.25*(12 - I1) = 15 - 1.25I1
5.25*I1 = 15

I1 = 2.86

I think I've messed up already here. Can anyone spot what I'm doing wrong??
 

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Gauss M.D. said:

Homework Statement



Find the current marked I3 in the circuit.

Homework Equations





The Attempt at a Solution



The voltage over R2 and R1 is the same. The current I0 (12mA) is the sum of I2 and I1.

I1*R1 = I2*R2:
4*I1 = 1.25*I2

It is wrong. The voltage over R3 and R4 is the same .

Gauss M.D. said:
I1 + I2 = 12 <=> I2 = 12 - I1

4*I1 = 1.25*(12 - I1) = 15 - 1.25I1
5.25*I1 = 15

I1 = 2.86

I think I've messed up already here. Can anyone spot what I'm doing wrong??
 
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Thanks! Is I2 still the sum of I3+I4 though? :S
 
Gauss M.D. said:
Thanks! Is I2 still the sum of I3+I4 though? :S

Sure.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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