To find David's velocity with respect to John at time t=1, differentiate their respective equations of motion: John's is Rj(t)=(t^2+3t)i + tj, and David's is Rd(t)=5ti+t^3j. The differentiation yields their velocities: vj(t) = (2t + 3)i + j for John and vd(t) = 5i + 3t^2j for David. Evaluating these at t=1 gives vj(1) = 5i + j and vd(1) = 5i + 3j. The relative velocity of David with respect to John is then calculated as vd(1) - vj(1) = 0i + 2j.
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