- #1

Painguy

- 120

- 0

## Homework Statement

You are given the following values for the errror function f HxL = erf HxL.

erf (0)= 0

erf (1) = 0.84270079

erf(.1)= 0.11246292

erf(.01) = 0.01128342

Use this information to approximate the value of erf '(1). Explain how you arrived at your answer.

## Homework Equations

## The Attempt at a Solution

I basically took the average from both sides of erf(.01)

(((erf(0)-erf(.01))/.01)+((erf(.01)-erf(.1))/(-.09)))/2 = (1.128342 + 1.124216667)/2 =1.126279335

I ended up with 1.126279335 so I'm assuming its something close to that like 1.12? Am I right or wrong?