Integration of exponential function times polynomial of fractional degree

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SUMMARY

The discussion centers on solving the Laplace transform of the function \(\mathcal{L}\{t^{\frac{1}{2}}\}\) using the formula \(\mathcal{L}\{t^\alpha\} = \frac{\Gamma{(\alpha + 1)}}{s^{\alpha+1}}\). The user, Andrew, initially struggles with the integral \(\int^\infty_0 {t^{\frac{1}{2}}e^{-t}dt}\) but later realizes that the Gamma function can be used directly to find the solution without performing the integral. The relationship between \(\Gamma(\frac{3}{2})\) and \(\Gamma(\frac{1}{2})\) is crucial, as it simplifies the problem significantly.

PREREQUISITES
  • Understanding of Laplace transforms
  • Familiarity with the Gamma function and its properties
  • Basic knowledge of differential equations
  • Ability to perform integration techniques
NEXT STEPS
  • Study the properties of the Gamma function, particularly \(\Gamma(\frac{1}{2})\) and \(\Gamma(\frac{3}{2})\)
  • Learn about the application of Laplace transforms in solving differential equations
  • Explore integration techniques related to exponential functions and polynomials
  • Investigate the relationship between the error function and the Gamma function
USEFUL FOR

Students and professionals in mathematics, particularly those focused on differential equations, Laplace transforms, and integral calculus. This discussion is beneficial for anyone looking to deepen their understanding of the Gamma function and its applications in solving integrals.

andyyee
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Homework Statement



I'm working out a differential equation problem that I am supposed to solve with the formula [itex]\mathcal{L}\{t^\alpha\} = \frac{\Gamma{(\alpha + 1)}}{s^{\alpha+1}}[/itex]. The problem is [itex]\mathcal{L}\{t^{\frac{1}{2}}\}[/itex] (finding the Laplace transform of the given function).

Homework Equations



[itex]\mathcal{L}\{t^\alpha\} = \frac{\Gamma(\alpha + 1)}{s^{\alpha+1}}, \alpha > -1[/itex]

[itex]\Gamma(\alpha) = \int^\infty_0{t^{\alpha-1}e^{-t}dt}, \alpha > 0[/itex]

The Attempt at a Solution



I plug it into the equation, and get [itex]\frac{\Gamma(\frac{3}{2})}{s^\frac{3}{2}} =[/itex] [itex]\frac{\int^\infty_0 {t^\frac{1}{2}e^{-t}dt}}{s^{3/2}}[/itex]. That's where I run into a problem, I have no idea how to solve that integral. I can't use integration by parts, because one term will never disappear or the original integral will not appear again as [itex]\int{vdu}[/itex], so that won't work. I looked it up on Wolfram|Alpha, and it gave me [itex]\frac{1}{2}\sqrt{\pi}\text{erf}{(\sqrt{t})} - e^{-t}\sqrt{t}[/itex] for the indefinite form and [itex]\frac{\sqrt{\pi}}{2}[/itex] for the definite form. It also cited some stuff about integrating the normal distribution and error form, but I don't understand what it is talking about. What I am unsure about is the steps involved in solving the integral, and is there a generalized solution (for the definite integral from 0 to [itex]\infty[/itex]) for other coefficient values in the power of the polynomial?

Thanks
Andrew
 
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But you don't have to do the integral. You have the LaPlace transform from your formula;

[tex]\frac{\Gamma(\frac 3 2)}{s^\frac 3 2}[/tex]

[itex]\Gamma(3/2)[/itex] is just a constant. Look in your text and see if it doesn't give you [itex]\Gamma(1/2)[/itex] and a relationship between the Gamma value at 3/2 and 1/2.
 
Thanks for the help :-). I completely overlooked the part in my book that mentioned an appendix, which happened to show some basic integration (for gamma of 1/2 using double integrals), as well as ways to solve similar gamma values without integration (simple algebra transformations using the already computed, given gamma of 1/2 and some other formulas). These forums are really great, because although Wolfram|Alpha gives me solutions, it does not tell me why (or to look closer at my book :-).

- Andrew
 

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