Find Determinant of 4x4 Matrix: Problem Solved

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Homework Help Overview

The discussion revolves around finding the determinant of a 4x4 matrix, specifically the matrix given as \(\begin{bmatrix}5&3&0&6\\4&6&4&12\\0&2&-3&4\\0&1&-2&2\end{bmatrix}\). Participants are exploring the methods of calculating the determinant using cofactor expansion.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to expand the determinant using the leftmost column, noting the presence of zeros to simplify calculations. They express uncertainty about their results, specifically why their computed determinant does not match the expected value of zero.
  • Another participant suggests checking arithmetic, indicating that they also arrive at zero for the cofactors.
  • A correction is raised regarding the elements used in the cofactor calculation, pointing out an error in the last row of one of the cofactors that could affect the determinant.

Discussion Status

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct assistance they can provide. The original poster has verified the determinants of smaller cofactors but remains confused about the overall determinant calculation.

themadhatter1
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Homework Statement


Find the Determinant.

\left[\begin{array}{cccc}5&3&0&6\\4&6&4&12\\0&2&-3&4\\0&1&-2&2\end{array}\right]

Homework Equations



The Attempt at a Solution


I'm not sure why I can't get the determinant of this one right.

I chose to use the left most column to expand on because the two zeros make it easier

I have 2 cofactors since the other 2 would be multiplied by 0. The 4 is negative in C_{31} because of the plus minus alternating pattern that is applied to the matrix.

C_{41}=5\left|\begin{array}{ccc}6&4&12\\2&-3&4\\-1&-2&2\end{array}\right|
C_{31}=-4\left|\begin{array}{ccc}3&0&6\\2&-3&4\\1&-2&2\end{array}\right|

C_{41}=5(-104)
C_{31}=-4(0)

If you add these you get -520, but the determinant of the 4x4 is 0. I also checked the determents of the smaller 3x3 cofactors and they are right. What am I doing wrong?
 
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themadhatter1 said:

Homework Statement


Find the Determinant.

\left[\begin{array}{cccc}5&3&0&6\\4&6&4&12\\0&2&-3&4\\0&1&-2&2\end{array}\right]


Homework Equations



The Attempt at a Solution


I'm not sure why I can't get the determinant of this one right.

I chose to use the left most column to expand on because the two zeros make it easier

I have 2 cofactors since the other 2 would be multiplied by 0. The 4 is negative in C_{31} because of the plus minus alternating pattern that is applied to the matrix.

C_{41}=5\left|\begin{array}{ccc}6&4&12\\2&-3&4\\-1&-2&2\end{array}\right|
C_{31}=-4\left|\begin{array}{ccc}3&0&6\\2&-3&4\\1&-2&2\end{array}\right|

C_{41}=5(-104)
C_{31}=-4(0)

If you add these you get -520, but the determinant of the 4x4 is 0. I also checked the determents of the smaller 3x3 cofactors and they are right. What am I doing wrong?

Check your arithmetic. I get 0 for both cofactors.
 
themadhatter1 said:
C_{41}=5\left|\begin{array}{ccc}6&4&12\\2&-3&4\\-1&-2&2\end{array}\right|

The last line should be [1, -2, 2] instead of [-1, -2, 2]. That would make it 0
 
Oh. haha you'd be right. Thanks!
 

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